If it's not what You are looking for type in the equation solver your own equation and let us solve it.
D( x )
x^2-1 = 0
x-1 = 0
x^2-1 = 0
x^2-1 = 0
1*x^2 = 1 // : 1
x^2 = 1
x^2 = 1 // ^ 1/2
abs(x) = 1
x = 1 or x = -1
x-1 = 0
x-1 = 0
x-1 = 0 // + 1
x = 1
x in (-oo:-1) U (-1:1) U (1:+oo)
2/(x-1)+1 = 4/(x^2-1) // - 4/(x^2-1)
2/(x-1)-(4/(x^2-1))+1 = 0
2/(x-1)-4*(x^2-1)^-1+1 = 0
2/(x-1)-4/(x^2-1)+1 = 0
(2*(x^2-1))/((x-1)*(x^2-1))+(-4*(x-1))/((x-1)*(x^2-1))+(1*(x-1)*(x^2-1))/((x-1)*(x^2-1)) = 0
2*(x^2-1)-4*(x-1)+1*(x-1)*(x^2-1) = 0
x^3+2*x^2-x^2-4*x-x+1+2 = 0
x^3+x^2-5*x+3 = 0
x^3+x^2-5*x+3 = 0
x^3+x^2-5*x+3 = 0
{ 1, -1, 3, -3 }
1
x = 1
x^3+x^2-5*x+3 = 0
1
x-1
x^2+2*x-3
x^3+x^2-5*x+3
x-1
x^2-x^3
2*x^2-5*x+3
2*x-2*x^2
3-3*x
3*x-3
0
x^2+2*x-3 = 0
DELTA = 2^2-(-3*1*4)
DELTA = 16
DELTA > 0
x = (16^(1/2)-2)/(1*2) or x = (-16^(1/2)-2)/(1*2)
x = 1 or x = -3
x in { -3, 1, 1}
(x+3)*(x-1)^2 = 0
((x+3)*(x-1)^2)/((x-1)*(x^2-1)) = 0
((x+3)*(x-1)^2)/((x-1)*(x^2-1)) = 0 // * (x-1)*(x^2-1)
(x+3)*(x-1)^2 = 0
( x+3 )
x+3 = 0 // - 3
x = -3
( x-1 )
x-1 = 0 // + 1
x = 1
x in { 1}
x = -3
| 2/3+4t=6t-2/15+2/5 | | -9p-6(2-3p)=5(p-2)-14 | | 45=t(t-4) | | 9+6(5x+10)= | | 42=8(m-2) | | 10x^2-13x+4= | | 2x+8(x-7)=2(x-16) | | 5t-7=5-t | | 16t^2-128t-16=0 | | 6x-3-10x+1=12x+16 | | 8(3x+7)= | | x=x+1/3 | | 5-x=2x+14 | | 3x-12-7x-14=-2x-26 | | 2(3v-8)=8 | | -6x-10=-12x-9 | | 3x-5+6=9x-6x+2 | | 9y-2y=56 | | 7(9-7(8-a))-9=9(7(9a-8)+6)-82 | | 4(3x-1)+(2x+3)(x-7)= | | 2/3+4t=6t-2/152/5 | | 1200x^3+5=0 | | 8(v+1)-2v=2(3v+2)-12 | | -6x+2-3=-4 | | -5u-0.4=-0.05 | | s=2*3.14rh+2*3.14r^2 | | 4/3x-7=0.3x+8 | | 4x=24whatisx | | 10x^2-29x-90=0 | | -4z-(-122)=62 | | 3*12+2y=18 | | -7(v+4)+4v+6=6v+6 |